High vs Low Anti Rise Bikes

20 hours ago Edited Date/Time 19 hours ago
Here's the weight distribution graphic I promised:Any questions?

Here's the weight distribution graphic I promised:

image 816.png?VersionId=9uc  t0boAkM7QR4dGHS0khojkoz2s
Bike Weight Distribution Downhill

Any questions?

So I went and grabbed my DH bike to see how the CG location stacks up. This is an easy experiment to do if anyone feels inclined to put some real numbers on themselves… measure the weight of you and your bike. In my case this is 190.4 lbs. Then find a nice level spot where you can balance with your bar end ever so slightly on a wall for support. Put the scale under the front wheel and then weight the bike however you see fit. Record that weight. (Total weight-front wheel weight)/total weight is the percentage of weight carried by the rear wheel. You can then find the X coordinate of your CG. With my weight shifted reasonably far back but not stretching it I got 41.4 lbs on the front wheel (78.26%). The bike in question has a 1299 mm wheelbase. (1-0.7826)*wheelbase is the horizontal distance from the rear axle to your CG. In my case here that’s 282 mm. Y height of CG is harder to estimate, but I’d put mine at maybe 645 mm.

Now with the weight distribution problem it’s a little more complicated than where the CG is relative to the front axle. How much braking force can be generated is a massive factor. If we assume as much braking force as friction allows, the angle of inclination actually factors out entirely and the end result is a function of coefficient of friction. In the case of my DH bike, the equation is 0.78-0.50μ. With a coefficient of friction of 0.5, that puts 53% of the weight on the rear wheel. For a tire on dry concrete, μ is 1 so on a super grippy surface you’ve still got 28% on the rear wheel. And if there’s no grip… you’re at the 78% rear wheel bias regardless of angle of inclination. 

8
Ride886
Posts
16
Joined
4/21/2026
Location
Bellingham, WA, USA
18 hours ago
Here's the weight distribution graphic I promised:Any questions?

Here's the weight distribution graphic I promised:

image 816.png?VersionId=9uc  t0boAkM7QR4dGHS0khojkoz2s
Bike Weight Distribution Downhill

Any questions?

So I went and grabbed my DH bike to see how the CG location stacks up. This is an easy experiment to do if anyone feels...

So I went and grabbed my DH bike to see how the CG location stacks up. This is an easy experiment to do if anyone feels inclined to put some real numbers on themselves… measure the weight of you and your bike. In my case this is 190.4 lbs. Then find a nice level spot where you can balance with your bar end ever so slightly on a wall for support. Put the scale under the front wheel and then weight the bike however you see fit. Record that weight. (Total weight-front wheel weight)/total weight is the percentage of weight carried by the rear wheel. You can then find the X coordinate of your CG. With my weight shifted reasonably far back but not stretching it I got 41.4 lbs on the front wheel (78.26%). The bike in question has a 1299 mm wheelbase. (1-0.7826)*wheelbase is the horizontal distance from the rear axle to your CG. In my case here that’s 282 mm. Y height of CG is harder to estimate, but I’d put mine at maybe 645 mm.

Now with the weight distribution problem it’s a little more complicated than where the CG is relative to the front axle. How much braking force can be generated is a massive factor. If we assume as much braking force as friction allows, the angle of inclination actually factors out entirely and the end result is a function of coefficient of friction. In the case of my DH bike, the equation is 0.78-0.50μ. With a coefficient of friction of 0.5, that puts 53% of the weight on the rear wheel. For a tire on dry concrete, μ is 1 so on a super grippy surface you’ve still got 28% on the rear wheel. And if there’s no grip… you’re at the 78% rear wheel bias regardless of angle of inclination. 

Have a look at Matt Beer's article from PB.  At 2:40 in the video you can see his weight distribution changing in real time.

That said, I don't need another Shockcraft branded drawing to tell me if I can use my rear brake on a steep trail. 30 some years of actual riding is a sufficient data point to know the answer is yes. Often and effectively.

9
Dougal - SC
Posts
49
Joined
8/17/2026
Location
Alexandra, NZ
2 hours ago
So I went and grabbed my DH bike to see how the CG location stacks up. This is an easy experiment to do if anyone feels...

So I went and grabbed my DH bike to see how the CG location stacks up. This is an easy experiment to do if anyone feels inclined to put some real numbers on themselves… measure the weight of you and your bike. In my case this is 190.4 lbs. Then find a nice level spot where you can balance with your bar end ever so slightly on a wall for support. Put the scale under the front wheel and then weight the bike however you see fit. Record that weight. (Total weight-front wheel weight)/total weight is the percentage of weight carried by the rear wheel. You can then find the X coordinate of your CG. With my weight shifted reasonably far back but not stretching it I got 41.4 lbs on the front wheel (78.26%). The bike in question has a 1299 mm wheelbase. (1-0.7826)*wheelbase is the horizontal distance from the rear axle to your CG. In my case here that’s 282 mm. Y height of CG is harder to estimate, but I’d put mine at maybe 645 mm.

Now with the weight distribution problem it’s a little more complicated than where the CG is relative to the front axle. How much braking force can be generated is a massive factor. If we assume as much braking force as friction allows, the angle of inclination actually factors out entirely and the end result is a function of coefficient of friction. In the case of my DH bike, the equation is 0.78-0.50μ. With a coefficient of friction of 0.5, that puts 53% of the weight on the rear wheel. For a tire on dry concrete, μ is 1 so on a super grippy surface you’ve still got 28% on the rear wheel. And if there’s no grip… you’re at the 78% rear wheel bias regardless of angle of inclination. 

That graphic is my old Bergamont Encore (475 reach) and measured weight distributions.  DH bikes used to be more rearward, but Enduro bikes have caught up enough that some companies are using the same frames for both!  

I think your tyre friction coefficients might be a bit optimistic.  Coefficient of 1 and higher required a very sticky and hot tyre on a clean surface.  I think 0.8 static is about where you'd be for a sticky MTB tyre on rock/concrete/asphalt.  Gravel/dirt is going to vary massively and worth testing. Anything wet is going to be very low.

This is good data from tractors:

https://agtiretalk.com/wp-content/uploads/2022/02/BKT2.png

Concrete/asphalt/rock static 0.75, dynamic a bit over 0.8.
Hard dirt static 0.5, dynamic (really digging in) almost 0.8
Loose static 0.4, really digging in a bit over 0.5

Problem with the back brake is it loses weight as you brake.
On flat ground seated you've generally got 2/3 weight on the back wheel.  But the harder you brake the more weight shifts forwards and off your back wheel.  Which 
Braking on hard ground (0.8 traction) with the back brake you're going to peak out about 2.6 m/s^2 (0.25 G force) decelleration using the back wheel (depending on geometry).
Braking on hard ground with the front wheel you're going to peak out about 8m/s^2 (0.8 G Force) (rear wheel zero weight).

Front wheel on hard ground and firm soil is ~3x more effective.  

Add in a down slope and that 3x number gets bigger.  To the point where the back wheel can't even hold the bike.

2
2 hours ago
That graphic is my old Bergamont Encore (475 reach) and measured weight distributions.  DH bikes used to be more rearward, but Enduro bikes have caught up...

That graphic is my old Bergamont Encore (475 reach) and measured weight distributions.  DH bikes used to be more rearward, but Enduro bikes have caught up enough that some companies are using the same frames for both!  

I think your tyre friction coefficients might be a bit optimistic.  Coefficient of 1 and higher required a very sticky and hot tyre on a clean surface.  I think 0.8 static is about where you'd be for a sticky MTB tyre on rock/concrete/asphalt.  Gravel/dirt is going to vary massively and worth testing. Anything wet is going to be very low.

This is good data from tractors:

https://agtiretalk.com/wp-content/uploads/2022/02/BKT2.png

Concrete/asphalt/rock static 0.75, dynamic a bit over 0.8.
Hard dirt static 0.5, dynamic (really digging in) almost 0.8
Loose static 0.4, really digging in a bit over 0.5

Problem with the back brake is it loses weight as you brake.
On flat ground seated you've generally got 2/3 weight on the back wheel.  But the harder you brake the more weight shifts forwards and off your back wheel.  Which 
Braking on hard ground (0.8 traction) with the back brake you're going to peak out about 2.6 m/s^2 (0.25 G force) decelleration using the back wheel (depending on geometry).
Braking on hard ground with the front wheel you're going to peak out about 8m/s^2 (0.8 G Force) (rear wheel zero weight).

Front wheel on hard ground and firm soil is ~3x more effective.  

Add in a down slope and that 3x number gets bigger.  To the point where the back wheel can't even hold the bike.

We all get that braking shifts weight forward. What I just walked through is how much weight you can end up with on the front and rear wheels in a certain scenario that involves braking as hard as grip will allow. Downslope does not factor into weight distribution. If you walk through the math you end up with a cos(theta) term in both the numerator and denominator that cancel out. 0.5 is a pretty reasonable number for loose soil such as a rake and ride and that yields about a 50/50 weight distribution on any slope with weight shifted rearward. You can easily end up with it biased even more rearward riding in the wet.

That plot does bring up an interesting thing about braking force on loose surfaces that happens to lend itself towards rear wheel braking. Wheel slip from the front wheel is generally not very tolerable especially if turning is involved but is required for max braking force. On the contrary the rear wheel can slip a ton. If you want hard braking that's less susceptible to the front wheel slipping and washing out maybe it's a good idea to bias weight rearward.

2
Dougal - SC
Posts
49
Joined
8/17/2026
Location
Alexandra, NZ
1 hour ago Edited Date/Time 36 minutes ago
We all get that braking shifts weight forward. What I just walked through is how much weight you can end up with on the front and...

We all get that braking shifts weight forward. What I just walked through is how much weight you can end up with on the front and rear wheels in a certain scenario that involves braking as hard as grip will allow. Downslope does not factor into weight distribution. If you walk through the math you end up with a cos(theta) term in both the numerator and denominator that cancel out. 0.5 is a pretty reasonable number for loose soil such as a rake and ride and that yields about a 50/50 weight distribution on any slope with weight shifted rearward. You can easily end up with it biased even more rearward riding in the wet.

That plot does bring up an interesting thing about braking force on loose surfaces that happens to lend itself towards rear wheel braking. Wheel slip from the front wheel is generally not very tolerable especially if turning is involved but is required for max braking force. On the contrary the rear wheel can slip a ton. If you want hard braking that's less susceptible to the front wheel slipping and washing out maybe it's a good idea to bias weight rearward.

Downslope drives your entire weight distribution.  This is due to your weight being above the ground line so slope changes the proportions.
The only time your values would cancel out is if COG was at ground level.  Which gets close for a split second after an OTB!

Moving your weight back isn't optional on steeps.  If you don't do it you're eating dirt.

Here is the resulting weight shifts and max traction on a 20° (36%) downslope:

image 823
Bike Braking Dynamics

The front braking is limited by stability (rear wheel lift), the rear is limited by the interplay of forward weight shift and traction.

1
1 hour ago
We all get that braking shifts weight forward. What I just walked through is how much weight you can end up with on the front and...

We all get that braking shifts weight forward. What I just walked through is how much weight you can end up with on the front and rear wheels in a certain scenario that involves braking as hard as grip will allow. Downslope does not factor into weight distribution. If you walk through the math you end up with a cos(theta) term in both the numerator and denominator that cancel out. 0.5 is a pretty reasonable number for loose soil such as a rake and ride and that yields about a 50/50 weight distribution on any slope with weight shifted rearward. You can easily end up with it biased even more rearward riding in the wet.

That plot does bring up an interesting thing about braking force on loose surfaces that happens to lend itself towards rear wheel braking. Wheel slip from the front wheel is generally not very tolerable especially if turning is involved but is required for max braking force. On the contrary the rear wheel can slip a ton. If you want hard braking that's less susceptible to the front wheel slipping and washing out maybe it's a good idea to bias weight rearward.

Yup good points! Rubber has the highest grip when there is a small amount of slip. Also your front tyre can't brake AND turn in equal amounts so even if you were braking with the front only, you better hope there aren't any turns on that trail! 

And because the friction coefficient (which is different to tractive efficiency...) gets lower as you increase vertical load, if you were to have 100% weight on the front wheel (which you don't) you would still have much less braking available anyway.

Also does anyone know the actual gradient of a "steep" trail? Most people here probably don't need convincing but if you stick your phone on the ground with the surface level app going you would see its no where near as high an angle as some would think

1
1 hour ago

They say Dead Dog is 32 degrees. Definitely not the steepest trail but the key is it’s constant with no catch berms for very long distances. This makes it a good test for this conversation as it’s all about what gives you maximum braking power. 

1 hour ago
Downslope drives your entire weight distribution.  This is due to your weight being above the ground line so slope changes the proportions.The only time your values...

Downslope drives your entire weight distribution.  This is due to your weight being above the ground line so slope changes the proportions.
The only time your values would cancel out is if COG was at ground level.  Which gets close for a split second after an OTB!

Moving your weight back isn't optional on steeps.  If you don't do it you're eating dirt.

Here is the resulting weight shifts and max traction on a 20° (36%) downslope:

image 823
Bike Braking Dynamics

The front braking is limited by stability (rear wheel lift), the rear is limited by the interplay of forward weight shift and traction.

Slope angle factors out entirely. You need to step through it by summing the moments about the front contact patch. These sketches work fine for reference, but you need to actually do the math. It's pretty easy to see how m, g, and Cos(theta) factor out, but I had it simplify for the sake of it. 

image 822
1
1 hour ago
Yup good points! Rubber has the highest grip when there is a small amount of slip. Also your front tyre can't brake AND turn in equal...

Yup good points! Rubber has the highest grip when there is a small amount of slip. Also your front tyre can't brake AND turn in equal amounts so even if you were braking with the front only, you better hope there aren't any turns on that trail! 

And because the friction coefficient (which is different to tractive efficiency...) gets lower as you increase vertical load, if you were to have 100% weight on the front wheel (which you don't) you would still have much less braking available anyway.

Also does anyone know the actual gradient of a "steep" trail? Most people here probably don't need convincing but if you stick your phone on the ground with the surface level app going you would see its no where near as high an angle as some would think

Yeah it's actually kind of comical and makes you feel like you can't ride anything steep some times. You may very well find you can't slow down on even maintain speed on a 25 degree decline.

AgrAde
Posts
248
Joined
5/21/2015
Location
., BV
29 minutes ago

Most people feel a lot of exposure over a scree slope and consider them too step to ride, and they're only 30 degrees or so.

Dougal - SC
Posts
49
Joined
8/17/2026
Location
Alexandra, NZ
26 minutes ago Edited Date/Time 19 minutes ago
Slope angle factors out entirely. You need to step through it by summing the moments about the front contact patch. These sketches work fine for reference...

Slope angle factors out entirely. You need to step through it by summing the moments about the front contact patch. These sketches work fine for reference, but you need to actually do the math. It's pretty easy to see how m, g, and Cos(theta) factor out, but I had it simplify for the sake of it. 

image 822

There are several ways to analyse this and they all give the same answers.  But the intermediate results are very different.  I think that's what's going on.  You're still talking static braking and not dynamic with the weight shift.

The bike in that graphic has a 2/3 rear weight distribution static, but rear only braking on the flat hits equialibrium at 0.21g decelleration which moves 21kg onto the front and kills your rear traction.

Everything sums about any point.  Doesn't matter if it's front tyre, rear tyre, COG etc.  But you can rotate the diagrams (slope angle) or rotate the vectors (use accelerations to represent slope).

The answers are all the same.  Back brake can hold a bike on 10 degrees and at ~45 degrees, depending on geometry, your back wheel is floating.

image 824.png?VersionId=Q8FXZd4dmhfI

 

Many people consider 20% (11 deg) a very steep slope.  It is if you're climbing.

Dougal - SC
Posts
49
Joined
8/17/2026
Location
Alexandra, NZ
10 minutes ago Edited Date/Time 3 minutes ago
So I went and grabbed my DH bike to see how the CG location stacks up. This is an easy experiment to do if anyone feels...

So I went and grabbed my DH bike to see how the CG location stacks up. This is an easy experiment to do if anyone feels inclined to put some real numbers on themselves… measure the weight of you and your bike. In my case this is 190.4 lbs. Then find a nice level spot where you can balance with your bar end ever so slightly on a wall for support. Put the scale under the front wheel and then weight the bike however you see fit. Record that weight. (Total weight-front wheel weight)/total weight is the percentage of weight carried by the rear wheel. You can then find the X coordinate of your CG. With my weight shifted reasonably far back but not stretching it I got 41.4 lbs on the front wheel (78.26%). The bike in question has a 1299 mm wheelbase. (1-0.7826)*wheelbase is the horizontal distance from the rear axle to your CG. In my case here that’s 282 mm. Y height of CG is harder to estimate, but I’d put mine at maybe 645 mm.

Now with the weight distribution problem it’s a little more complicated than where the CG is relative to the front axle. How much braking force can be generated is a massive factor. If we assume as much braking force as friction allows, the angle of inclination actually factors out entirely and the end result is a function of coefficient of friction. In the case of my DH bike, the equation is 0.78-0.50μ. With a coefficient of friction of 0.5, that puts 53% of the weight on the rear wheel. For a tire on dry concrete, μ is 1 so on a super grippy surface you’ve still got 28% on the rear wheel. And if there’s no grip… you’re at the 78% rear wheel bias regardless of angle of inclination. 

Let's see if we can find some common ground on flat braking.

Your bike, 1299 wheelbase, 86kg total weight, in rearward position you've got 22/64kg fr/rear split.
Using a 1m COG height (round numbers, can adjust later) I get max rear braking at 3m/s^2 (0.3G).  This results in a forward weight shift of 20.3kg and dynamic weights of 42F and 44R kg.

Front brake you can pull 9.5 m/s^2 (just over 1G) IFF you've got the grip.  Front is a a shade over 3x as effective as the rear on flat ground.

Post a reply to: High vs Low Anti Rise Bikes

The Latest